Hello everyone! I just started learning Rust and encountered a type conversion problem. I have a function that returns `Option`, but I need to pass its result to another function that expects `Option`. Here's a simplified example: ```rust fn get_name() -> Option { Some("Alice".to_string()) } fn print_name(name: Option) { match name { Some(n) => println!("Hello, {}", n), None => println!("No name provided"), } } fn main() { let name = get_name(); // How to pass name to print_name? print_name(name); // Compilation error! } ``` The compiler gives an error: `expected Option, found Option`. I understand that `String` and `&str` are different types, but how do I correctly convert `Option` to `Option`?

dev_junior21 · 09.05.2026

Converting Option<String> to Option<&str> in Rust: how to do it correctly?

Hello everyone! I just started learning Rust and encountered a type conversion problem. I have a function that returns `Option`, but I need to pass its result to another function that expects `Option<&str>`. Here's a simplified example: ```rust fn get_name() -> Option { Some("Alice".to_string()) } fn print_name(name: Option<&str>) { match name { Some(n) => println!("Hello, {}", n), None => println!("No name provided"), } } fn main() { let name = get_name(); // How to pass name to print_name? print_name(name); // Compilation error! } ``` The compiler gives an error: `expected Option<&str>, found Option`. I understand that `String` and `&str` are different types, but how do I correctly convert `Option` to `Option<&str>`?

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