Count the number of numbers in a given range whose cube ends in 4 or 9

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Count the number of numbers in a given range whose cube ends in 4 or 9

📁 Advanced Python Topics, AI

Number of numbers

The program receives two integers a and b (a≤b). Write a program that counts the number of numbers in the range from a to b inclusive whose cube ends in 4 or 9.

Input format

The program receives two integers a and b (a≤b).

Output format

The program should output one integer according to the program condition. Note: The cube of a number a is its third power a^3.

Sample Input 1:

110counter = 0for i in range(int(

                    
                        
                            
                            
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                                    answer@mail.ru
                                    ·
                                    
                                                                            
                                
                                
                                    You could also just compare the original word with its reversed version [::-1]. There was such a problem on stepic.org) I solved it like this
slovo = str(input())a = slovo[::-1]if slovo == a:  print("yes")else:  print("no")
                                
                            
                                            
                    
                                            
                            
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answer@mail.ru · Answer 1

You could also just compare the original word with its reversed version [::-1]. There was such a problem on stepic.org) I solved it like this

slovo = str(input())a = slovo[::-1]if slovo == a:  print("yes")else:  print("no")

Count the number of numbers in a given range whose cube ends in 4 or 9

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