Why can you return std::unique_ptr from a function without std::move?

Hello! I recently started learning C++11 and smart pointers, and I got confused with std::unique_ptr. I know that unique_ptr cannot be copied — only moved. To move, std::move() is usually used. But I noticed strange behavior: when I write a function that creates and returns a unique_ptr, the compiler doesn't complain even if I don't call std::move(). Here's an example: ```cpp #include std::unique_ptr createInt() { std::unique_ptr ptr = std::make_unique(42); return ptr; // Without std::move() — and it works! } int main() { std::unique_ptr p = createInt(); return 0; } ``` Why does this compile? After all, unique_ptr prohibits copying! If I try to do the same with a regular variable in another function, for example