on the distant planet XB-103, a research robot geologist collects samples of minerals from the conveyor tape. Each type of mineral has its own unique numerical identifier (ID). The robot control system should work as efficiently as possible, therefore, to optimize the storage of the robot, it is necessary to transfer only one number to the central computer at the end of the shift: what was the maximum length of the continuous series of samples of the same type. The shift of the robot ends when a special calibration sample with ID is 0.
rnyou are given a sequence of numerical minerals of minerals. The sequence always ends with the number 0, which means the end of the shift and is not the ID of the mineral. Determine the largest number of the same IDs in a row in this sequence.
Entire natural numbers are introduced, each from a new line. The sequence ends with the number 0.
One number & mdash; The maximum length of the continuous sequence of the same elements.
1
7
7
7
2
2
9
0
3
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# Инициализируем переменные для подсчета
# max_len - хранит максимальную найденную длину серии
# current_len - хранит длину текущей серии одинаковых чисел
# prev_n - хранит предыдущее число для сравнения с текущим
max_len = 0
current_len = 0
# Используем -1 как начальное значение, так как ID минералов - натуральные числа
prev_n = -1
# Запускаем бесконечный цикл, который прервется при вводе 0
while True:
# Считываем очередной ID и преобразуем его в целое число
n = int(input())
# Условие выхода из цикла - конец смены
if n == 0:
break
# Сравниваем текущий ID с предыдущим
if n == prev_n:
# Если они равны, увеличиваем счетчик текущей серии
current_len += 1
else:
# Если числа не равны, значит серия прервалась.
# Сначала проверяем, не была ли закончившаяся серия самой длинной
if current_len > max_len:
max_len = current_len
# Начинаем новую серию с текущего числа. Ее длина равна 1.
current_len = 1
# Обновляем "предыдущее" число
prev_n = n
# После завершения цикла нужно выполнить еще одну проверку.
# Это необходимо для случая, когда самая длинная серия оказалась в самом конце
# последовательности, прямо перед нулем.
if current_len > max_len:
max_len = current_len
# Выводим результат
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