Determine the sequence of 1 2 2 3 3 3 4 4 4 4 5 5 5 5 5 on Python 3

I try to solve the problem:

Write a program that displays part of the sequence of 1 2 2 3 3 4 4 4 4 5 5 5 5 5 ... (the number is repeated so many times, which is equal). The input program transmits a positive integer N&MDash; So many elements of the sequence should display the program. At the output, a sequence of numbers recorded through a gap in one line is expected.

for example, if n = 7, then the program should dial 1 2 2 3 3 3 4.

sample input: 7

sample output: 1 2 2 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 4

This is what it tus out, the problem is that it doesn’t work on large numbers.

  a =  int  ( input  ()) b =  '' '   for  i  in   range  (a+ 1 ):  b = b + ( str  (i) +  '' )*it  print  (b [ 0 : a* 2 ])