🎉 恭喜! 🎉
你出色地完成了任务!这是一个不小的挑战,但你找到了正确答案。你离编程大师又近了一步!继续保持,每一步都让你更强大。
在古老而神秘的城市中,有一座图书馆,里面藏有一本能够预测未来事件的魔法日历。在这本日历中,每一年都可能具有特殊的意义,而城中的魔法师们依赖于精确的天文计算。图书馆的守护者——智者阿莉斯塔,委托你一项重要任务:判断指定的年份是否为闰年。这一知识将帮助他正确配置魔法仪式和预言。
编写一个程序,根据给定的年份数字,判断它是否为闰年。
年份的数字(整数)。
答案是判断该年份是否为闰年(输出:'yes' 或 'no')。
2024年
是
You can nest some conditional statements (if) into others to create more complex and multi-level checks. This is useful when the next action depends on several consecutive conditions.
The key point here is the correct indentation (usually 4 spaces), which shows Python which block of code belongs to which condition.
Example:
x = 10
if x > 5:
print("First check passed: x is greater than 5.")
if x < 20:
print("Second check passed: x is also less than 20.")
else:
print("Second check failed: x is at least 20.")
else:
print("First check failed: x is less than or equal to 5.")
A useful tip: Try not to create too many nesting levels (3 or more). Deeply embedded code becomes difficult to read and understand. Often, complex nesting can be simplified by using logical operators.
Logical operators in Python are used to combine two or more conditions. They allow you to build complex logic without putting conditions into each other. The main logical operators are and, or and not.
| The | Name | Description |
|---|---|---|
or |
logical "OR" | Returns True if at least one condition is true. |
and |
logical "And" | Returns True only if both conditions are true. |
not |
logical "NOT" (negation) | Inverts the result: True becomes False and vice versa. |
Examples:
a = 5
b = 7
# and: both conditions must be true
s1 = a > 3 and b < 10 # True and True -> True
# or: at least one condition must be true
s2 = a != 5 or b >= 7 # False or True -> True
# not: inverts the result
s3 = not (a < b) # not (True) -> False
When using and, the result will be true only if both operands are true. When using or, it is sufficient for at least one of the operands to be true. The not operator turns a lie into the truth and vice versa.
Analysis of a complex example:
a, b, c = 7, 10, 11
# Original expression:
print(not(a > 7 and b <= 10) or c != 17)
# Let's take it step by step:
# 1. a > 7 -> 7 > 7 -> False
# 2. b <= 10 -> 10 <= 10 -> True
# 3. (False and True) -> False
# 4. not(False) -> True
# 5. c != 17 -> 11 != 17 -> True
# 6. True or True -> True
# Result: True
A useful tip: To improve readability and avoid errors in complex expressions, always use parentheses () to explicitly specify the order of calculations, even if you remember the precedence of operators (not has the highest priority, then and, then or).
The ternary operator is a compact way to write a simple if-else condition that returns a value. It allows you to assign a variable a value depending on the condition, and all this in one line.
Syntax: [value if true] if [condition] else [value if false]
Examples:
x = 10
# If x > 5, result will be 100, otherwise 200
result = 100 if x > 5 else 200
print(result) # Will output: 100
y = 20
# Assign the larger of the two values to the variable z
z = x if x > y else y
print(z) # Outputs: 20
# Assign a text value
result_text = "positive" if x > 0 else "non-positive"
print(result_text) # Outputs: positive
A useful tip: The ternary operator is great for simple assignments. However, if the logic becomes more complicated or if, depending on the condition, you need to perform different actions (rather than just return a value), it is better to use a full-fledged if-else construct to preserve the readability of the code.
If the condition body (if, elif, or else) consists of only one instruction, Python allows you to write it in the same line after the colon.
Example:
x = 10
if x > 5: print("x is greater than 5")
Important style note: Although this notation is syntactically correct, it is often not recommended by the Python Code Style Guide (PEP 8). Placing instructions on a separate line with indentation improves readability and is a generally accepted standard. Use a one-line entry with care, mostly for very simple and obvious actions.
# Считываем введенный год и преобразуем его в целое число
year = int(input())
# Проверяем условия високосного года, используя логические операторы "и" (and), "или" (or)
# Условие 1: Год делится на 4 без остатка (year % 4 == 0) И при этом не делится на 100 (year % 100 != 0)
# Условие 2: Год делится на 400 без остатка (year % 400 == 0)
if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
# Если одно из двух основных условий истинно, то год високосный
print("YES")
else:
# В противном случае год обычный
print("NO")
🎉 恭喜! 🎉
你出色地完成了任务!这是一个不小的挑战,但你找到了正确答案。你离编程大师又近了一步!继续保持,每一步都让你更强大。
AD
广告
正在运行代码...